A 4.53 kg particle has a velocity of vx =
3.98 m/s and vy = −3.16 m/s.
Find the magnitude of its total momentum.
Answer in units of kg · m/s
V8y^2=X^2 + Y^2 = 3.98^2 + (-3.16)^2=25.83
V = 5.08 m/s.
Momentum = M*V = 4.53 * 5.08 = 23 kg.m/s
3.98 m/s and vy = −3.16 m/s.
Find the magnitude of its total momentum.
Answer in units of kg · m/s
V = 5.08 m/s.
Momentum = M*V = 4.53 * 5.08 = 23 kg.m/s