Al saves pennies. He agreed to give 5/11 of his pennies to bev . If she would give 5/11 of what she got from al to carl and in return if he would give 5/11 of what he got from bev to danni, carl and agreed and danni recived 750 pennies . How many pennies did al have?
To solve this problem, we can work backwards starting with Danni's total number of pennies.
Given that Danni received 750 pennies, we know that this is 5/11 of what Carl received. Let's call the number of pennies Carl received as C.
So, 5/11 of C is equal to 750 pennies. To find C, we can multiply 750 by 11/5.
C = 750 * 11/5
C = 1650
Now that we know Carl received 1650 pennies, we can find out how many pennies Bev received. According to the problem, Bev received 5/11 of what Al gave her. Let's call the number of pennies Al gave Bev as B.
So, 5/11 of B is equal to 1650 pennies. To find B, we can multiply 1650 by 11/5.
B = 1650 * 11/5
B = 3630
Lastly, we need to determine the number of pennies Al had before giving some to Bev. According to the problem, Al gave 5/11 of his pennies to Bev. Therefore, 5/11 of Al's total pennies is equal to 3630 pennies.
We can set up the following equation to find Al's total number of pennies (A):
5/11 * A = 3630
To solve for A, we can multiply both sides of the equation by 11/5:
A = 3630 * 11/5
A = 7986
Therefore, Al had a total of 7986 pennies.
b = 5a/11
c = 5b/11
d = 5c/11
what is the "agreed"?
plug in your final result
c+?+d=750
and then start substituting in to get a