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empty cruble-34.69g
crucible+ magnesium- 34.86g
crucible+magnesium oxide - 34.97g

How can i find the number of moles of magnesium present at the start of the reaction

How can i also find the total number of magnesium oxide molecules present at the end of the reaction

  • chem -

    mols Mg = mass Mg/atomic mass Mg.
    Wouldn't mass Mg be (mass xble+Mg) - (mass empty xble)?

    Now think about the MgO. Now that you see how easy it is to get mass Mg, wouldn't a very similar tactic obtain mass MgO.

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