Quadratic Graphs

Can you please check if my values are correct?

y=x^2-4x

x= -4 so y= 0
x= -3 so y= -3
x= -2 so y= -4
x= -1 so y= -3
x= 0 so y= 0
x= 1 so y= -3
x= 2 so y= 14

Thank you

To check if the values are correct, we can plug them back into the equation and see if they give us the correct values of y.

The equation given is:
y = x^2 - 4x

Let's substitute the given values of x and check if they match the corresponding values of y:

For x = -4:
y = (-4)^2 - 4(-4)
y = 16 + 16
y = 32

For x = -3:
y = (-3)^2 - 4(-3)
y = 9 + 12
y = 21

For x = -2:
y = (-2)^2 - 4(-2)
y = 4 + 8
y = 12

For x = -1:
y = (-1)^2 - 4(-1)
y = 1 + 4
y = 5

For x = 0:
y = (0)^2 - 4(0)
y = 0 + 0
y = 0

For x = 1:
y = (1)^2 - 4(1)
y = 1 - 4
y = -3

For x = 2:
y = (2)^2 - 4(2)
y = 4 - 8
y = -4

Comparing the values you provided with the results obtained, it seems that there is a mistake for the values of x = -3 and x = 2. The correct values of y for these values of x are y = 21 and y = -4, respectively.