if 5.00 ml of 1.66x10^-1 M HCl solution is diluted to exactly 250.0 ml with water, what is the concentration of the resulting solution?
0.166 M x (5.00/250.0) = ?
To find the concentration of the resulting solution, we can use the concept of dilution. The formula for dilution is:
M1 x V1 = M2 x V2
Where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution
In this case, we have:
M1 = 1.66 x 10^-1 M
V1 = 5.00 ml = 5.00 x 10^-3 L
M2 = ? (what we want to find)
V2 = 250.0 ml = 250.0 x 10^-3 L
Plugging in the values into the formula, we have:
(1.66 x 10^-1 M) x (5.00 x 10^-3 L) = M2 x (250.0 x 10^-3 L)
Simplifying the equation:
8.30 x 10^-4 = M2 x (250.0 x 10^-3)
Dividing both sides by (250.0 x 10^-3 L):
M2 = 8.30 x 10^-4 / (250.0 x 10^-3 L)
M2 = 3.32 x 10^-3 M
Therefore, the concentration of the resulting solution is 3.32 x 10^-3 M.
To get the concentration of the resulting solution, you need to use the principle of dilution, which states that the initial moles of solute remain constant after dilution.
First, calculate the number of moles of HCl in the initial solution:
Moles of solute = Concentration x Volume
Moles of HCl = (1.66x10^-1 M) x (5.00 mL) = 8.30x10^-4 moles
Since the number of moles of HCl remains constant after dilution, we can equate it to the number of moles in the resulting solution:
Moles of HCl = Moles of resulting solution
8.30x10^-4 moles = (Concentration of resulting solution) x (Volume of resulting solution)
Concentration of resulting solution = 8.30x10^-4 moles / (250.0 mL)
Now, convert the volume from milliliters to liters:
Concentration of resulting solution = 8.30x10^-4 moles / (0.2500 L)
Finally, calculate the concentration:
Concentration of resulting solution = 3.32x10^-3 M
Therefore, the concentration of the resulting solution is 3.32x10^-3 M.