Question

This one confused me since it revolved around what seemed like dividing trig function by another function

Write the following expression in terms of the tangent function
2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2))

= ?

I know tan t = sin t / cos t. So would I multiply by the reciprocal? Or since cos / sin = cot would I put the 2 over cotangent. this one confused me

Answer 1

2 / ((cos(r^2 - s^2) / (sin(r^2 - s^2))

= 2 * (sin(r^2 - s^2) / (cos(r^2 - s^2)
= 2 tan (r^2 - s^2)