Mary is y years old.
Write an algebraic expression in terms of y for the age of
A) her brother, who is 4 years older.
B) her mother, who is 3 times as old.
C) her sister, who is 2 years younger.
y + 4
3y
y-2
Think about it like this, if Mary had four brothers, she is Mary's age plus the age of 4 brothers, but we don't know it, so Y + 4 is good enough.
3y, because Mary had a little lamb that was 3.
And Y-2 because its her and 2 others who died in the car crash. Get it?
No?
Good.
i do
To write algebraic expressions for the age of Mary's brother, mother, and sister, we need to consider the given information about Mary's age.
A) Mary's brother is 4 years older than Mary. Since Mary is y years old, we can represent Mary's brother's age as y + 4.
B) Mary's mother is 3 times as old as Mary. To express this algebraically, we multiply Mary's age (y) by 3, so Mary's mother's age can be written as 3y.
C) Mary's sister is 2 years younger than Mary. Thus, Mary's sister's age can be represented as y - 2.
In summary:
A) Mary's brother's age = y + 4
B) Mary's mother's age = 3y
C) Mary's sister's age = y - 2
y + 4
3y
y - 2