If a line with a slope of -2 crosses the y-axis at (0, 3), what is the equation of the line?
point slope form:
y-y1=m(x-x1)
m=slope
y1=3
x1=0
y-3=-4(x-0)
y-3=-4x
y=-4x+3 <--- equation of the line
To find the equation of a line with a given slope and y-intercept, you can use the slope-intercept form of a linear equation, which is y = mx + b.
In this case, the slope of the line is -2, and the y-intercept is (0, 3). The y-intercept is the point where the line crosses the y-axis, and it is given as (0, 3), which means the value of y when x is 0 is 3.
Since the line crosses the y-axis at (0, 3), the y-intercept is 3. The slope is -2.
Now we can substitute the values into the slope-intercept form of the equation:
y = mx + b
y = -2x + 3
Therefore, the equation of the line is y = -2x + 3.