What is the temperature of 0.65mol {\rm mol} of gas at a pressure of 1.5atm {\rm atm} and a volume of 12.6L {\rm L} ?
Use PV = nRT
T will have units of kelvin
STOP! I NEED ANSWERS NOT FORMULA. THANK YOU THOUGH.
To find the temperature of the gas, you can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure of the gas (in atm)
V = Volume of the gas (in L)
n = Amount of substance (in moles)
R = Ideal gas constant (0.0821 L·atm/(mol·K))
T = Temperature of the gas (in Kelvin)
First, let's rearrange the equation to solve for temperature:
T = PV / (nR)
Now, we can substitute the given values:
P = 1.5 atm
V = 12.6 L
n = 0.65 mol
R = 0.0821 L·atm/(mol·K)
Plugging these values into the equation:
T = (1.5 atm) * (12.6 L) / (0.65 mol) * (0.0821 L·atm/(mol·K))
Now we can calculate the temperature:
T = 29.344 K
Therefore, the temperature of 0.65 mol of gas at a pressure of 1.5 atm and a volume of 12.6 L is approximately 29.344 Kelvin (K).