Question

Find the exact value and approximate. 11^ -x+4 = 5^ 3x-2 (-x+4)log11 = (3x-2)log5

Answer 1

(-x+4)log11 = (3x-2)log5

-log11 x + 4log11 = 3log5 x - 2log5
-(log11+3log5)x = -(2log5 + 4log11)

x = (2log5+4log11)/(log11+3log5)

and, of course, you could go on and say

x = log(5^2*11^4)/log(11*5^3)
= log366025/log1375

or even

log₁₃₇₅366025