Mia is on a planet where g=10 m/s^2. she is standing on a bathroom scale in an elevator. the scale reads 500N. the elevator accelerates upward with an acceleration of 5.0m/s^2 what would the scale read now

To determine what the scale would read now, we need to consider the forces acting on Mia.

When Mia is standing on the bathroom scale, there are two forces acting on her: her weight (mg) and the normal force from the scale.

Weight is the force acting on an object due to gravity, and it is given by the formula: weight = mass × acceleration due to gravity (mg).

In this case, Mia's weight is calculated as follows: weight = mass × (acceleration due to gravity)
= mass × 10 m/s^2.

Since the scale reads 500N, which is the normal force exerted by the scale on Mia, we know that the normal force and weight are equal in magnitude. Therefore, we can equate the two forces:

Normal force = Weight.

Now, let's consider the forces acting on Mia when the elevator accelerates upward with an acceleration of 5.0m/s^2:

1. The force of gravity (weight) remains the same because it depends on the acceleration due to gravity, not on the elevator's acceleration. So, the weight is still mass × 10 m/s^2.

2. The normal force exerted by the scale changes. It must now oppose the combination of Mia's weight and the upward force due to the elevator's acceleration.

To calculate the normal force in this new scenario, we can use the equation:

Normal force = Mia's weight + Force due to acceleration

Now, the force due to the acceleration of the elevator is given by the formula: Force = mass × acceleration.

Substituting the given values, we have:

Force due to acceleration = mass × elevator's acceleration
= mass × 5.0 m/s^2.

Finally, we can calculate the new normal force:

Normal force = Mia's weight + Force due to acceleration
= mass × 10 m/s^2 + mass × 5.0 m/s^2
= mass × (10 m/s^2 + 5.0 m/s^2)
= mass × 15 m/s^2.

Therefore, the scale would read the new normal force, which is 15 times Mia's mass.

Please provide Mia's mass, and I can calculate the new reading on the scale.