If there are 25 mg of water in a typical drop of water, how many drops of water
would react completely with 2 mmol of phenylmagnesium bromide?
How do I set up the problem?
First you have to find the amount of water (in grams) that will react with 2 mol of phenylmagesium bromine. Then you convert the grams into mg. Finally, you divid by 25.
Reply if you want the answer.
How do you find the amount of water that reacted 2 mol of phenylmagesium bromine?
You have to first right the balanced formula
MgBr + H2O --> Benzene + Mg(OH)Br
This means that 2 mols of water will react with 2 moles of phenylmagnesium bromide
2 mol of water equals 36 gram or 36000 mg so the answer is 1440 drops of water
But remember it is 2 mmol of water so it is actually 1.44 drops of water
To set up the problem, we first need to determine the amount of water that would react completely with 2 mmol of phenylmagnesium bromide.
1. Determine the molar mass of phenylmagnesium bromide (C6H5MgBr):
- Carbon (C): 6 x 12.01 g/mol
- Hydrogen (H): 5 x 1.01 g/mol
- Magnesium (Mg): 24.31 g/mol
- Bromine (Br): 79.90 g/mol
- Add up the atomic masses: (6 x 12.01) + (5 x 1.01) + 24.31 + 79.90 = 134.25 g/mol
2. Convert the millimoles (mmol) of phenylmagnesium bromide to moles:
- 2 mmol * (1 mol / 1000 mmol) = 0.002 mol
3. Use the molar ratio between phenylmagnesium bromide and water to find the amount of water in moles. The balanced chemical equation for the reaction will provide the stoichiometric ratio:
- In this case, we'll need the balanced chemical equation for the reaction between phenylmagnesium bromide and water. Without the specific reaction equation, we won't be able to provide an accurate answer.
Once you have the balanced chemical equation, you'll need to determine the stoichiometric ratio between phenylmagnesium bromide and water. This ratio tells you how many moles of water react per mole of phenylmagnesium bromide.
4. Convert the moles of water to milligrams (mg):
- Multiply the moles of water by the molar mass of water, which is approximately 18.015 g/mol:
- 0.002 mol x (18.015 g / mol) x (1000 mg / g) = X mg
Finally, divide X mg with 25 mg, which is the amount of water in a typical drop, to find the number of drops of water that would react completely with 2 mmol of phenylmagnesium bromide.