What is the kinetic energy of a 0.02 kg bullet that is traveling 300 m/s? Express your answer in joules.
900J
To find the kinetic energy of the bullet, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the bullet is 0.02 kg and the velocity is 300 m/s, you can plug these values into the formula:
Kinetic Energy = (1/2) * 0.02 kg * (300 m/s)^2
Now, let's calculate it step by step:
Step 1: Square the velocity:
(300 m/s)^2 = 90000 m^2/s^2
Step 2: Multiply the squared velocity by the mass:
0.02 kg * 90000 m^2/s^2 = 1800 kg m^2/s^2
Step 3: Simplify the units:
1 J = 1 kg m^2/s^2, so 1800 kg m^2/s^2 is equivalent to 1800 J.
Therefore, the kinetic energy of the bullet is 1800 joules.