A student mixed two clear liquids together in a beaker and a solid precipitate formed. His data is shown in the table below.
Liquid reactant A = 10 g
Liquid reactant B = 17 g
Beaker + solid product= 32 g
What is the mass of the beaker?
A. 5 g
B. 10 g
C. 15 g
D. 17 g
E. 32 g
Is the answer A?
Thank you
The answer is a "5g"
the whole QC is
1.A
2.D
3.B
4.C
Due to the conservation of mass, the mass of the reactants is equal to the mass of the products.
Mass(A) + Mass(B) = Mass Solid Product
10g + 17g = 27g
Mass(beaker) = Mass(Beaker + product) - Mass (product)
So Mass(Beaker) = 32g - 27g = 5g
So your answer is "A. 5g."
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To find the mass of the beaker, we can subtract the combined mass of the reactants from the combined mass of the beaker and the solid product.
Given data:
Mass of liquid reactant A = 10 g
Mass of liquid reactant B = 17 g
Combined mass of beaker and solid product = 32 g
To find the mass of the beaker, we can use the following formula:
Mass of beaker = Combined mass of beaker and solid product - (Mass of liquid reactant A + Mass of liquid reactant B)
Mass of beaker = 32 g - (10 g + 17 g)
Mass of beaker = 32 g - 27 g
Mass of beaker = 5 g
So, the correct answer is A. 5 g.