How many joules of heat are required to melt 20.0 kg of ice at 0°C?
Specific heat of ice is
2100J/kg°C
Would I need to multiply 2100*20.0
Nevermind
Its
(20.0)(3.35*10^5)=6700000
Or 6.70*10^6
3.35*10^5 was the heat fusion of ice
To find out how many joules of heat are required to melt 20.0 kg of ice at 0°C, we need to use the formula:
Q = m × Hf
Where:
Q = amount of heat energy (in joules)
m = mass of the substance being heated (in kilograms)
Hf = heat of fusion
In this case, we are melting ice, so the heat of fusion represents the amount of energy required to change one kilogram of ice at its melting point to water at the same temperature.
The heat of fusion for ice is 334,000 joules per kilogram.
So, plugging in the values:
Q = 20.0 kg × 334,000 J/kg
Q = 6,680,000 joules
Therefore, 6,680,000 joules of heat are required to melt 20.0 kg of ice at 0°C.