can you explain this to me please?

Consider the binomial distribution where n = 11 and p = 0.05.
Find the mean and standard deviation of this binomial distribution.

To find the mean and standard deviation of a binomial distribution, we can use the following formulas:

1. Mean (µ) = n * p
2. Standard Deviation (σ) = √(n * p * (1 - p))

Given that n = 11 and p = 0.05, we can substitute these values into the formulas to calculate the mean and standard deviation.

1. Mean (µ) = 11 * 0.05 = 0.55
So, the mean of this binomial distribution is 0.55.

2. Standard Deviation (σ) = √(11 * 0.05 * (1 - 0.05))
= √(11 * 0.05 * 0.95)
= √(0.5225)
≈ 0.723
So, the standard deviation of this binomial distribution is approximately 0.723.

Therefore, the mean is 0.55 and the standard deviation is approximately 0.723.

Sure! To find the mean and standard deviation of a binomial distribution, we can use the following formulas:

Mean (μ) = n * p

Standard Deviation (σ) = sqrt(n * p * (1 - p))

In this case, we are given that n = 11 and p = 0.05.

Let's substitute these values into the formulas:

Mean (μ) = 11 * 0.05 = 0.55

Standard Deviation (σ) = sqrt(11 * 0.05 * (1 - 0.05))

Before calculating the standard deviation, we need to calculate (1 - 0.05) = 0.95:

Standard Deviation (σ) = sqrt(11 * 0.05 * 0.95)

Now, we can simplify the equation:

Standard Deviation (σ) = sqrt(0.5225) ≈ 0.722

So, the mean of this binomial distribution is 0.55, and the standard deviation is approximately 0.722.