How many grams of the adipic acid (C6H10O4) could form from the reaction of 15.00 g of cyclohexane (C6H12) with the 25.00 g of oxygen?
Will the formula be...
2O2 + C6H12 ---> C6H10O4
To find out how many grams of adipic acid (C6H10O4) can form from the given reactants, we need to determine the limiting reactant. The limiting reactant is the one that is completely consumed and determines the amount of product formed.
First, let's calculate the number of moles for each reactant:
1. Cyclohexane (C6H12):
Given mass of cyclohexane = 15.00 g
Molar mass of cyclohexane (C6H12) = (12.01 g/mol × 6) + (1.01 g/mol × 12) = 84.18 g/mol
Number of moles of cyclohexane = mass / molar mass = 15.00 g / 84.18 g/mol
2. Oxygen (O2):
Given mass of oxygen = 25.00 g
Molar mass of oxygen (O2) = 2 × 16.00 g/mol = 32.00 g/mol
Number of moles of oxygen = mass / molar mass = 25.00 g / 32.00 g/mol
Next, let's calculate the mole ratio between cyclohexane and adipic acid:
From the balanced equation:
2O2 + C6H12 → C6H10O4
The mole ratio between cyclohexane and adipic acid is 1:1. This means that for every mole of cyclohexane reacted, we will obtain one mole of adipic acid.
Now, we compare the moles of cyclohexane and oxygen to determine the limiting reactant:
Moles of cyclohexane = 15.00 g / 84.18 g/mol
Moles of oxygen = 25.00 g / 32.00 g/mol
The limiting reactant is determined by the reactant that produces fewer moles of the desired product.
Since the mole ratio between cyclohexane and adipic acid is 1:1, the number of moles of cyclohexane represents the maximum number of moles of adipic acid that can form. Therefore, 15.00 g of cyclohexane will produce 15.00 g of adipic acid.
Hence, the amount of adipic acid that can form from the given reaction is 15.00 grams.