I need help because I don't understand how to solve this equation.
37. x/a - 1 = y/b for x
So... does it mean solve for x?
39. V = 1/3 * pi * radius^2 * h for h
So... does it mean solve for h?
As you can see, I am really confused.
Please help.
example:
V=1/3 PI r^2 H
solve for h.
divide both sides by 1/3 pI r^2
h=V/(1/3 PI r^2)=3V/PIr^2
I'm sorry. I don't really get what you are doing. Can you explain?
The questions are asking you to rearrange the equations for a given variable.
remember, what you do to one side, you have to do to the other.
so
x/a - 1 = y/b for x
add 1 to each side
x/a = y/b + 1
now multiply by a
x= ay/b + a
Of course, I'll be happy to help you understand how to solve these equations!
Let's start with the first equation, 37.
The equation is:
x/a - 1 = y/b
To solve for x, we need to isolate x on one side of the equation. Here's the step-by-step process:
1. Start by adding 1 to both sides of the equation:
x/a - 1 + 1 = y/b + 1
This simplifies to:
x/a = y/b + 1
2. Next, multiply both sides of the equation by a:
a * (x/a) = a * (y/b + 1)
The a in the numerator and denominator cancel out, giving us:
x = ay/b + a
So the solution to the equation is:
x = ay/b + a
Now, let's move on to the second equation, 39.
The equation is:
V = 1/3 * π * radius^2 * h
To solve for h, we'll follow a similar procedure to isolate h on one side of the equation:
1. Start by dividing both sides of the equation by 1/3 * π * radius^2:
V / (1/3 * π * radius^2) = h
2. Simplify the expression on the left side:
V multiplied by the reciprocal of 1/3 * π * radius^2:
V * (3 * π * radius^2) = h
So the solution to the equation is:
h = V * (3 * π * radius^2)
I hope this clears up the confusion for you! If you have any more questions, feel free to ask.