I need help because I don't understand how to solve this equation.

37. x/a - 1 = y/b for x

So... does it mean solve for x?

39. V = 1/3 * pi * radius^2 * h for h

So... does it mean solve for h?

As you can see, I am really confused.

Please help.

example:

V=1/3 PI r^2 H
solve for h.

divide both sides by 1/3 pI r^2

h=V/(1/3 PI r^2)=3V/PIr^2

I'm sorry. I don't really get what you are doing. Can you explain?

The questions are asking you to rearrange the equations for a given variable.

remember, what you do to one side, you have to do to the other.

so

x/a - 1 = y/b for x

add 1 to each side

x/a = y/b + 1

now multiply by a

x= ay/b + a

Of course, I'll be happy to help you understand how to solve these equations!

Let's start with the first equation, 37.

The equation is:
x/a - 1 = y/b

To solve for x, we need to isolate x on one side of the equation. Here's the step-by-step process:

1. Start by adding 1 to both sides of the equation:
x/a - 1 + 1 = y/b + 1
This simplifies to:
x/a = y/b + 1

2. Next, multiply both sides of the equation by a:
a * (x/a) = a * (y/b + 1)
The a in the numerator and denominator cancel out, giving us:
x = ay/b + a

So the solution to the equation is:
x = ay/b + a

Now, let's move on to the second equation, 39.

The equation is:
V = 1/3 * π * radius^2 * h

To solve for h, we'll follow a similar procedure to isolate h on one side of the equation:

1. Start by dividing both sides of the equation by 1/3 * π * radius^2:
V / (1/3 * π * radius^2) = h

2. Simplify the expression on the left side:
V multiplied by the reciprocal of 1/3 * π * radius^2:
V * (3 * π * radius^2) = h

So the solution to the equation is:
h = V * (3 * π * radius^2)

I hope this clears up the confusion for you! If you have any more questions, feel free to ask.