The wheels, axle, and handles of a wheelbarrow weigh 60.0 N. The center of gravity of the wheelbarrow alone is 0.600 m from the axel. The distance from the axle to the hands of the operator is 1.3 m. The force applied by the operator to the end of the handles is 250 newtons. The load chamber and contents is positioned 0.400 meters from the axle. What weight, in newton s, is the camber and its contents?

Question

The wheels, axle, and handles of a wheelbarrow weigh 60.0 N. The center of gravity of the wheelbarrow alone is 0.600 m from the axel. The distance from the axle to the hands of the operator is 1.3 m. The force applied by the operator to the end of the handles is 250 newtons. The load chamber and contents is positioned 0.400 meters from the axle. What weight, in newton s, is the camber and its contents?

i don't even know where to begin..

Answer 1

Start out by defining the rotational axis at the wheel since all of the distances from that point are given. Both the weight of the wheelbarrow and the weight of the load are acting upon the wheel in a clockwise direction, so they are negative. The force applied up is counterclockwise, so it is positive. Using sum of the torques, we get an equation like this: WL= (FdF +WdW)/dWL.

Answer 2

No worries! I can help you break down the problem step by step.

First, let's identify all the components and distances mentioned in the problem:

1. Total weight of the wheelbarrow (wheels, axle, and handles) = 60.0 N
2. Distance from the center of gravity of the wheelbarrow (alone) to the axle = 0.600 m
3. Distance from the axle to the hands of the operator = 1.3 m
4. Force applied by the operator to the end of the handles = 250 N
5. Distance from the axle to the load chamber and its contents = 0.400 m

Now, to solve for the weight of the load chamber and its contents, we can use the principle of moments or torque.

The principle of moments states that the sum of the clockwise moments about any point on an object must be equal to the sum of the anticlockwise moments about the same point. In this case, we can choose the axle as our point of reference.

Let's break down the moments:

1. The moment due to the weight of the wheelbarrow alone is given by:
Moment_wheelbarrow = Weight_wheelbarrow × distance_wheelbarrow
Moment_wheelbarrow = 60.0 N × 0.600 m

2. The moment due to the force applied by the operator is given by:
Moment_operator = Force_operator × distance_operator
Moment_operator = 250 N × 1.3 m

3. The moment due to the weight of the load chamber and its contents is given by:
Moment_load = Weight_load × distance_load
We want to solve for Weight_load.

Using the principle of moments, we have:
Moment_wheelbarrow + Moment_operator = Moment_load

Now, let's substitute the known values:
60.0 N × 0.600 m + 250 N × 1.3 m = Weight_load × 0.400 m

Simplifying the equation:
36.0 Nm + 325.0 Nm = 0.400 m × Weight_load
361.0 Nm = 0.400 m × Weight_load

Finally, let's solve for Weight_load:
Weight_load = 361.0 Nm / 0.400 m

Calculating this value will give you the weight of the load chamber and its contents in newtons.