Search results for "a monky climbs 4 metres of a pole in 1 minute, but slips 2 metres in next minute.in how much time he will reach the top of a pole 15 metres long?assume that he starts from the bottom of the pole."
Hmm… The wording in this problem is a little tricky to me, so I'm assuming that its an alternating pattern (poor monkey).
For the first minute the monkey is at 4 meters
For the second minute monkey is at 2 meters ( because he slips down)
So basically every 2 minutes, he's climbing 2 meters
so every minute he's climbing 1 meter
so it's going to take that monkey 15mins to climb 15 meters ( man that monkey is slow!)
Not quite.
After 12 minutes he has climbed 12 meters
In the 13th minute, he climbs the final 3 meters and is done.
Final time is thus 12:45
Ah, that is true! at 12 minutes he did climb 12 meters
and it took him another .45 seconds to climb the rest.
Wow, I completely neglected some stuff here.
Thanks for clarifying Steve!
Well, as long as I'm clarifying
:-) :-) :-)
That would be 45 seconds, not .45 seconds
Or, if you insist on decimals, try .75 minutes!
To find out how much time it will take for the monkey to reach the top of the 15-meter pole, we need to calculate the number of climbs and slips required.
1. Calculate the net distance covered by the monkey in each cycle (climb + slip).
- The monkey climbs 4 meters in 1 minute.
- The monkey slips 2 meters in the next minute.
Therefore, in every two-minute cycle, the monkey covers a net distance of 4 - 2 = 2 meters.
2. Calculate the number of complete two-minute cycles required to cover the entire distance of 15 meters.
- Divide the total distance of 15 meters by the net distance covered in each cycle (2 meters).
Therefore, the number of cycles required is 15 / 2 = 7.5 cycles.
Note: Since the monkey cannot have a partial climb or slip, we cannot have 0.5 cycles.
3. Calculate the total time required by multiplying the number of cycles by the time taken in each cycle (2 minutes).
Therefore, the total time required is 7.5 * 2 = 15 minutes.
However, it is important to note that there is no such thing as half a cycle in this context. So, the monkey will reach a position 14 meters above the ground within 14 minutes, but it cannot reach the full height of the 15-meter pole.