A gold bar has a mass of 250 grams and is heated from 25 degrees Celsius to 55 degrees Celsius. How much heat did the gold bar absorb? The specific heat of gold is 0.13J/g*degrees C.
q = heat absorbed = mass Au x specific heat Au x (Tfinal-Tinitial)
32.5
To calculate the heat absorbed by the gold bar, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat absorbed (in joules)
m = mass of the gold bar (in grams)
c = specific heat of gold (in J/g*°C)
ΔT = change in temperature (in °C)
Given:
m = 250 grams
c = 0.13 J/g*°C
ΔT = 55°C - 25°C = 30°C
Now, we can substitute the given values into the formula and solve for Q:
Q = 250 g * 0.13 J/g*°C * 30°C
Q = 3250 J
Therefore, the gold bar absorbed 3250 joules of heat.
To find out how much heat the gold bar absorbed, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat absorbed (in Joules)
m is the mass of the gold bar (in grams)
c is the specific heat of gold (in J/g*degrees C)
ΔT is the change in temperature (in degrees Celsius)
Given:
m = 250 grams
c = 0.13 J/g*degrees C
ΔT = 55 degrees Celsius - 25 degrees Celsius = 30 degrees Celsius
Now, we can substitute these values into the formula to calculate the amount of heat absorbed:
Q = 250 grams * 0.13 J/g*degrees C * 30 degrees Celsius
First, we need to convert the mass from grams to kilograms:
250 grams = 250/1000 = 0.25 kilograms
Now, we can substitute the converted mass into the formula:
Q = 0.25 kilograms * 0.13 J/g*degrees C * 30 degrees Celsius
Simplifying the equation:
Q = 0.25 kilograms * 0.13 J/g*degrees C * 30 degrees Celsius
= 0.25 * 0.13 * 30 J
= 0.975 J
Therefore, the gold bar absorbed approximately 0.975 Joules of heat.