I am still having problems this question
2. Review Examples 7.3 and 7.4, as well as the equation for E in the chapter notes.
Suppose an e−1 in an H atom has a transition from n = 3 to n = 2.
a. Determine the energy (E) of the released photon.
b. Convert E to and .
what type of light is emitted.
Show all units and conversion factors.
(1/4-1/9) x 2.179 x 0^-18 which equals 3.03 x 10^19 then u set up equation to lambda equals hc/e 6.626 x 10^-34x3.00 x 10^8/3.03 x 10^19 I got 6.20 x 10. ^-7 also is there an easier way to search for previous questions posted?
I can't read the funny blocks before E and after and. If you are asking if there is easier way to solve for lambda, yes you can use 1/lambda = R(1/4-1/9) with R the Rydberg constant of 1.0973E7 m^-1.
Those places you have 10^19 should be 10^-19. For lambda I obtain 6.56E-7 or 656 nm or 6560 A.