The length of a rectangle is 3 times the width. If the perimeter is to be at least 48 meters, what are the possible values for the width? (If the perimeter is at least 48 meters, then it is greater than or equal to 48 meters.)
2(w+3w) >= 48
4w >= 24
w >= 6
To find the possible values for the width of the rectangle, we need to set up an equation based on the given information.
Let's assume the width of the rectangle is 'w' meters.
According to the given information, the length of the rectangle is 3 times the width, which means the length is 3w meters.
The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width.
So, in this case, the perimeter of the rectangle is 48 meters or greater. Therefore, we can write the equation as:
48 ≤ 2(3w + w)
Simplifying the equation:
48 ≤ 2(4w)
48 ≤ 8w
Now, we can solve for 'w' by dividing both sides of the equation by 8:
48/8 ≤ w
6 ≤ w
So, the possible values for the width 'w' are any value greater than or equal to 6.