what mass of nitrogen gas is required to react completely with 2.79 of hydrogen gas to produce ammonia?
N2 + 3H2 ==> 2NH3
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols N2.
Now convert mols N2 to grams. g = mols x molar mass = ?
To find the mass of nitrogen gas required to react completely with hydrogen gas to produce ammonia, we need to balance the chemical equation for the reaction.
The balanced chemical equation for the reaction is:
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
To find the mass of nitrogen gas required, we can follow these steps:
Step 1: Calculate the number of moles of hydrogen gas.
Given mass of hydrogen gas = 2.79 g
Molar mass of hydrogen gas (H2) = 2 g/mol
Number of moles of hydrogen gas = mass / molar mass
Number of moles of hydrogen gas = 2.79 g / 2 g/mol
Number of moles of hydrogen gas = 1.395 mol
Step 2: Calculate the number of moles of nitrogen gas.
Since 3 moles of H2 react with 1 mole of N2, the number of moles of N2 can be calculated using the ratio:
Number of moles of N2 = (Number of moles of H2) / 3
Number of moles of N2 = 1.395 mol / 3
Number of moles of N2 = 0.465 mol
Step 3: Calculate the mass of nitrogen gas.
Given molar mass of nitrogen gas (N2) = 28 g/mol
Mass of nitrogen gas = number of moles x molar mass
Mass of nitrogen gas = 0.465 mol x 28 g/mol
Mass of nitrogen gas = 13.02 g
Therefore, the mass of nitrogen gas required to react completely with 2.79 g of hydrogen gas to produce ammonia is 13.02 g.
To find the mass of nitrogen gas required to react completely with the given mass of hydrogen gas, you need to first balance the chemical equation for the reaction between nitrogen gas and hydrogen gas to form ammonia. The balanced equation is:
N2 + 3H2 -> 2NH3
From the balanced equation, you can see that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia.
Next, you need to find the number of moles of hydrogen gas given the mass of hydrogen gas (2.79 g) and its molar mass (which is 2 g/mol). The molar mass of hydrogen (H2) is 2 g/mol because the atomic mass of hydrogen is 1 g/mol, and there are 2 hydrogen atoms in one molecule of H2.
Number of moles of hydrogen gas = mass of hydrogen gas / molar mass of hydrogen gas
= 2.79 g / 2 g/mol
= 1.395 mol
Since the stoichiometry of the balanced equation tells us that 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas, we can conclude that 1.395 moles of hydrogen gas would react with (1.395 mol / 3 mol) = 0.465 moles of nitrogen gas.
Finally, to calculate the mass of nitrogen gas, you need to multiply the number of moles of nitrogen gas by its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol because the atomic mass of nitrogen is 14 g/mol, and there are two nitrogen atoms in one molecule of N2.
Mass of nitrogen gas = number of moles of nitrogen gas * molar mass of nitrogen gas
= 0.465 mol * 28 g/mol
= 13.02 g
Therefore, the mass of nitrogen gas required to react completely with 2.79 g of hydrogen gas to produce ammonia is 13.02 g.