A car accelerates from rest at 2.57 m/s2.
What is the velocity at the end of 5.4 s?
Answer in units of m/s
Vo = 0
V = ?
t = 5.4 s.
a = (V-Vo)/t = 2.57 m/s^2
(V-0)/5.4 = 2.57. Solve for V.
To find the velocity of the car at the end of 5.4 seconds, we can use the kinematic equation:
v = u + at
where:
v = final velocity (what we are trying to find)
u = initial velocity (which is 0 m/s because the car starts from rest)
a = acceleration of the car (given as 2.57 m/s^2)
t = time (given as 5.4 s)
Now, let's substitute the given values into the equation:
v = 0 m/s + (2.57 m/s^2)(5.4 s)
Calculating the result:
v = 0 m/s + 13.878 m/s
Therefore, the velocity of the car at the end of 5.4 seconds is 13.878 m/s.