A titration of 15.75mL HCL of an unknown molarity requires 20.35mL of 0.0903M NaOH solution. What is the molarity of the HCl solution?
HCl + NaOH ==> NaCl + H2O
mols NaOH = M x L = ?
Using the coefficients in the balanced equation, convert mols NaOH to mols HCl. You can see the ratio is 1 mol HCl to 1 mol NaOH; therefore, mols HCl = mols NaOH.
Then M HCl = mols HCl/L HCl.
C1V1=C2V2 law can be applied because the ratio is 1:1
To find the molarity of the HCl solution, you can use the equation:
M1V1 = M2V2
Where:
M1 = molarity of the HCl solution
V1 = volume of the HCl solution
M2 = molarity of the NaOH solution
V2 = volume of the NaOH solution
In this case, you know that:
M2 = 0.0903M (molarity of the NaOH solution)
V2 = 20.35mL (volume of the NaOH solution)
V1 = 15.75mL (volume of the HCl solution)
Now you can substitute the known values into the equation:
M1 * 15.75mL = 0.0903M * 20.35mL
Rearranging the equation to solve for M1:
M1 = (0.0903M * 20.35mL) / 15.75mL
M1 = 0.1180 M
Therefore, the molarity of the HCl solution is approximately 0.1180 M.