How many atoms of nitrogen are in 3.00g of N2O5?
How many nitrogen atoms are present in 25.00 g of N2O5
How many nitrogen atoms are present in 25.00g of N2O5
How many nitrogen atoms are present in 25.00g of N2O5?
Useless
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=3454
Aga mabola bola
To find the number of atoms of nitrogen in 3.00g of N2O5, you need to use the Avogadro's number and the molar mass of N2O5.
1. Find the molar mass of N2O5:
- Nitrogen (N) has a molar mass of 14.01 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- N2O5 has two nitrogen atoms and five oxygen atoms, so the molar mass is:
Molar mass of N2O5 = (2 x Molar mass of N) + (5 x Molar mass of O)
= (2 x 14.01 g/mol) + (5 x 16.00 g/mol)
= 284.04 g/mol
2. Calculate the number of moles of N2O5:
- Moles = Mass / Molar mass
- Moles of N2O5 = 3.00 g / 284.04 g/mol
= 0.01056 mol
3. Use the mole ratio to find the number of moles of nitrogen:
- N2O5 has 2 nitrogen atoms per molecule, so the mole ratio is 2:1.
- Moles of nitrogen = 0.01056 mol x 2
= 0.02112 mol
4. Finally, use Avogadro's number to convert the number of moles of nitrogen to the number of atoms:
- Avogadro's number (NA) is approximately 6.022 x 10^23 atoms/mol.
- Number of atoms of nitrogen = Moles of nitrogen x NA
= 0.02112 mol x 6.022 x 10^23 atoms/mol
= 1.270 x 10^22 atoms
Therefore, there are approximately 1.270 x 10^22 atoms of nitrogen in 3.00g of N2O5.
mols N2O5 = grams/molar mass
mols N atoms = 2x that since there are two N atoms/molecule N2O5.
Then 1 mol N atoms contain 6.02E23 atoms so ? mols N atoms will contain ......