The system of blocks shown in the diagram below is being accelerated to the right at 4.4 m/s2

What is the applied force

Small box mass- 0.10 kg
Big box mass - 0.20 kg
Acceleration - 4.4 m/s2
Coefficient kinetic - 0.35

To find the applied force in this scenario, we need to first identify the forces acting on the system of blocks. These forces include: the applied force (F_app), the force of gravity (F_g), and the force of friction (F_friction).

The force of gravity acting on each block can be calculated using the formula F_g = m * g, where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2).

For the small box:
F_g (small box) = 0.10 kg * 9.8 m/s^2

For the large box:
F_g (large box) = 0.20 kg * 9.8 m/s^2

Next, we need to determine the force of friction using the formula F_friction = μ * F_n, where μ is the coefficient of kinetic friction and F_n is the normal force exerted on the block.

The normal force, F_n, is equal to the force of gravity acting on each block since the blocks are resting on a horizontal surface without any vertical motion.

For the small box:
F_n (small box) = F_g (small box)

For the large box:
F_n (large box) = F_g (large box)

Finally, we can find the applied force, F_app, using Newton's second law of motion: F_app = (m * a) + F_friction.

For the small box:
F_app (small box) = (0.10 kg * 4.4 m/s^2) + (0.35 * F_n (small box))

For the large box:
F_app (large box) = (0.20 kg * 4.4 m/s^2) + (0.35 * F_n (large box))

By substituting the values obtained in the previous steps for F_g and F_n into the equations above, we can calculate the applied force for each block.