A bicycle tire fitted was fitted with the air pressure of 75 psi at temperature 19 degree C riding the bike on a asphalt on a hot day increases temperature of the tire to 58 degree C. The volume increase by 4% . What is the new pressure

(P1V1/T1) = (P2V2/T2)

I would make up a convenient number for V1, something like 10 which makes V2 = 10.4. Then substitute and solve for P2. Don't forget T must be in kelvin.

20

To find the new pressure, we can use the ideal gas law, which states that the pressure of a gas is proportional to its temperature (assuming constant volume). The equation for the ideal gas law is:

P₁/T₁ = P₂/T₂

Where:
P₁ and T₁ are the initial pressure and temperature
P₂ and T₂ are the final pressure and temperature

Let's plug in the given values into the equation:

P₁ = 75 psi (initial pressure)
T₁ = 19 °C (initial temperature)
T₂ = 58 °C (final temperature)

Converting the temperatures to Kelvin:
T₁ = 19 + 273 = 292 K
T₂ = 58 + 273 = 331 K

Now we can rewrite the equation with the given values:

75 psi / 292 K = P₂ / 331 K

Next, we can solve for P₂ by multiplying both sides of the equation by 331:

(75 psi / 292 K) * 331 K = P₂

Simplifying the equation:

P₂ = (75 psi * 331 K) / 292 K

P₂ ≈ 84.90 psi

Therefore, the new pressure of the bicycle tire is approximately 84.90 psi.

To find the new pressure of the bicycle tire, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature measured in Kelvin.

First, we need to convert the temperatures from Celsius to Kelvin:
Initial temperature (T1) = 19°C + 273.15 = 292.15 K
Final temperature (T2) = 58°C + 273.15 = 331.15 K

Next, let's calculate the volume increase. We know that the volume has increased by 4%, so the new volume (V2) will be 104% of the initial volume (V1):
V2 = V1 + (4/100) * V1
V2 = 1.04 * V1

Now, we need to find the ratio of the initial volume to the final volume:
V1/V2 = (P1/P2) * (T2/T1)
(1.04 * V1) / V1 = (P1/P2) * (331.15 K/292.15 K)
1.04 = (P1/P2) * (331.15 K/292.15 K)

Since we are looking for the new pressure (P2), we can rearrange the equation:
(P2/P1) = 1.04 * (292.15 K/331.15 K)
P2 = P1 * (1.04 * 292.15 K/331.15 K)

Now we can substitute the given initial pressure (P1 = 75 psi):
P2 = 75 psi * (1.04 * 292.15 K/331.15 K)

Calculating this expression gives us the new pressure (P2) of the bicycle tire after the temperature increase.