If a 40 m rope is cut into two pieces in the ratio 3:5, how long is each piece?
I tried it but I checked it and it was wrong, please help.
To solve this problem, you can set up a proportion using the given ratio:
Let x represent the length of the first piece.
Then the length of the second piece is 40 - x.
We can now set up the proportion:
x / (40 - x) = 3/5
To solve for x, cross-multiply:
5x = 3(40 - x)
Now, distribute and simplify:
5x = 120 - 3x
8x = 120
x = 120 / 8
x = 15
Therefore, the length of the first piece is 15 meters, and the length of the second piece is 40 - 15 = 25 meters.
To solve this problem, we need to use the concept of ratios.
Let's assume that the ratio between the two pieces is 3:5. This means that the first piece is represented by 3x and the second piece is represented by 5x, where x is a common factor.
According to the given information, the total length of the rope is 40 meters. Therefore, we can set up the equation:
3x + 5x = 40
Combining like terms, we have:
8x = 40
To solve for x, we divide both sides of the equation by 8:
x = 40/8
x = 5
Now that we have the value of x, we can substitute it back into the expressions for the two pieces:
First piece = 3x = 3(5) = 15 meters
Second piece = 5x = 5(5) = 25 meters
So, the first piece is 15 meters long and the second piece is 25 meters long.
If the pieces are in the ratio 3:5 it means that if you divide the rope into 3+5=8 pieces, one part has 3 lengths, and the other has 5.
So, since 40/8 = 5, the pieces have lengths 15 and 25
15:25 = 3:5