Juan measured the location for the bookcase and realized that his

shelves can be no more than 1 3/4 feet wide.What is the maximum number of shelves Juan could build for this new bookcase using the lumber he bought?
How many DVD cases will he be able to store on each of the
shorter shelves?How many paperback books will he be able to store on each of the
shorter shelves?

help plz asap

Answer please

What type of wave is a radio wave?-------- is an infrared wave?----------

10, 16, and 5

To determine the maximum number of shelves Juan could build for the bookcase using the lumber he bought, we need to divide the total width of the bookcase by the maximum width of each shelf.

First, let's convert 1 3/4 feet to a decimal.

To convert fractions to decimals, you divide the numerator (the top number) by the denominator (the bottom number). For 3/4, since it's out of 4, you would divide 3 by 4:

3 ÷ 4 = 0.75

Therefore, 1 3/4 is equal to 1.75 feet.

Now, suppose the total width of the bookcase is X feet. To find the maximum number of shelves, we divide X by 1.75:

Number of shelves = X / 1.75

It seems we don't have enough information about the width of the bookcase, so we'll move on to the other questions.

To determine the number of DVD cases that can be stored on each of the shorter shelves, we need to know the dimensions of the DVD cases. Once you have those dimensions, divide the width of the shelf (1 3/4 feet or 1.75 feet) by the width of each DVD case.

Similarly, to determine the number of paperback books that can be stored on each of the shorter shelves, we need to know the dimensions of the paperback books. Once you have those dimensions, divide the width of the shelf (1 3/4 feet or 1.75 feet) by the width of each paperback book.

Please provide the dimensions of the DVD cases and paperback books, and if available, the total width of the bookcase, so I can help you with the calculations.