Two toy ducks attached to each other by a string, are being pulled by a child. The front duck is m1= 5.0 kg and the back duck is m2= 2.0 kg. The happy guy pulls them with a force of 10 N and friction exists. The toys are moving with constant velocity.
A) if the coefficient of kinetic friction is = 0.12, find the force of friction which is acting on the second duck.
B) calculate the tension in the string connecting the ducks
A) To find the force of friction acting on the second duck, we can use the formula:
Force of friction = coefficient of friction * normal force
In this case, the normal force on the second duck is equal to the weight of the second duck, which can be calculated by multiplying its mass (m2) by the acceleration due to gravity (9.8 m/s^2).
Normal force on the second duck = m2 * g
Therefore, the force of friction on the second duck can be calculated as:
Force of friction = coefficient of friction * (m2 * g)
Substituting the given values, we have:
Force of friction = 0.12 * (2.0 kg * 9.8 m/s^2)
Calculating the above expression, the force of friction on the second duck is approximately 2.35 N.
B) To calculate the tension in the string connecting the ducks, we can consider the forces acting on the first and second duck separately.
For the first duck, we have the force of tension pulling it forward (which is the same as the force of tension pulling the second duck backward), the force of friction, and the force applied by the child. Since the toys are moving at a constant velocity, the net force acting on the first duck must be zero.
Net force on the first duck = Force of tension - Force of friction - Force applied by child
Substituting the given force applied by the child (10 N) and the force of friction (calculated to be 2.35 N), we have:
Force of tension - 2.35 N - 10 N = 0
Rearranging the equation, the force of tension is:
Force of tension = 2.35 N + 10 N
Simplifying, the tension in the string connecting the ducks is approximately 12.35 N.