Can't figure this one out. The oceans' tide levels vary based on the phases of the moon. Find the percent decrease in tide levels when high tide is 4.25 ft and low tide is 0.75 ft above sea level.

I tried it and I think the answer is 82% am I right

correct

To find the percent decrease in tide levels, we first need to calculate the difference between the high tide and low tide.

The difference between high tide and low tide is obtained by subtracting the low tide measurement from the high tide measurement:

Difference = High tide - Low tide

Given that the high tide is 4.25 ft and the low tide is 0.75 ft above sea level, the difference is:

Difference = 4.25 ft - 0.75 ft
Difference = 3.5 ft

Now that we have calculated the difference, we can find the percent decrease in tide levels. To do this, we need to determine what percentage the difference is of the high tide.

Percent Decrease = (Difference / High tide) * 100%

Substituting the values, we get:

Percent Decrease = (3.5 ft / 4.25 ft) * 100%

Calculating this expression gives us:

Percent Decrease ≈ 82.35%

Therefore, the percent decrease in tide levels when the high tide is 4.25 ft and the low tide is 0.75 ft above sea level is approximately 82.35%.