two forces are applied to a 40kg object. one force is 50N and the other is 60N. if the forces are perpendicular to another, what will the resultant acceleration of the object be?
What is sqrt(50^2+60^2) ?
that force=m*a solve for a.
sqrt(50^2+60^2)
= 78.1
F=ma
78.1=(40)a ----> 78.1/40=a
a= 1.95m/s^2 is this correct? :)
yes.
thank you so much! definitely appreciate the help.
To find the resultant acceleration of the object, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Step 1: Find the net force acting on the object.
Since the forces are perpendicular to each other, we can use the Pythagorean theorem to find the magnitude of the net force.
Net force = √(50^2 + 60^2)
Net force = √(2500 + 3600)
Net force = √(6100)
Net force ≈ 78.15 N
Step 2: Use Newton's second law to find the resultant acceleration.
acceleration = Net force / mass
acceleration = 78.15 N / 40 kg
acceleration ≈ 1.95375 m/s²
Therefore, the resultant acceleration of the object will be approximately 1.95375 m/s².