What mass of phosphoric acid will be produced from the reaction of 10.00g of P4O10 with 12g water?
write the equation
P4O10 + 6H2O>> 4H3PO4
figure the mole of P4O10 you have in 10 g
figure the moles of water you have in 12 g
You need six moles of water for each mole of P4O10.
so which is the limiting reactant (least), moles of P4O10, or six times moles of water?
the limiting reactant is whichever of those is the smallest.
Then, moles acid= 4 times moles of limiting reactant, and convert that to grams of acid.
To determine the mass of phosphoric acid produced from the given reaction, we first need to write and balance the chemical equation:
P4O10 + 6H2O -> 4H3PO4
According to the balanced equation, 1 mole of P4O10 reacts with 6 moles of H2O to produce 4 moles of H3PO4.
Step 1: Find the molar mass of P4O10 (Phosphorus pentoxide)
P4 = 4 * Atomic Mass of phosphorus
= 4 * 30.97 g/mol
= 123.88 g/mol
O10 = 10 * Atomic Mass of oxygen
= 10 * 16.00 g/mol
= 160.00 g/mol
Molar mass of P4O10 = 123.88 g/mol + 160.00 g/mol
= 283.88 g/mol
Step 2: Convert grams of P4O10 to moles using its molar mass
Number of moles of P4O10 = Mass of P4O10 / Molar mass of P4O10
= 10.00 g / 283.88 g/mol
≈ 0.035194 mol
Step 3: Use the stoichiometry of the balanced equation to determine the moles of H3PO4 produced.
According to the balanced equation:
1 mole of P4O10 produces 4 moles of H3PO4
Moles of H3PO4 = Moles of P4O10 * (4 moles H3PO4 / 1 mole P4O10)
= 0.035194 mol * (4 mol / 1 mol)
= 0.140776 mol
Step 4: Find the molar mass of H3PO4 (Phosphoric acid)
H3 = 3 * Atomic mass of hydrogen
= 3 * 1.01 g/mol
= 3.03 g/mol
P = Atomic mass of phosphorus
= 30.97 g/mol
O4 = 4 * Atomic mass of oxygen
= 4 * 16.00 g/mol
= 64.00 g/mol
Molar mass of H3PO4 = 3.03 g/mol + 30.97 g/mol + 64.00 g/mol
= 98.00 g/mol
Step 5: Convert moles of H3PO4 to grams using its molar mass
Mass of H3PO4 = Moles of H3PO4 * Molar mass of H3PO4
= 0.140776 mol * 98.00 g/mol
≈ 13.80 g
Therefore, approximately 13.80 grams of phosphoric acid (H3PO4) will be produced from the reaction of 10.00 grams of P4O10 with 12 grams of water.