1.) Robin hood shoots an arrow up in the night sky. What is the acceleration at the very top of its path?

2.) Juan's car has an acceleration = -2.76m/s^2 and a velocity = 43m/s. Is he slowing down or speeding up?

1.) To determine the acceleration at the very top of the arrow's path, we need to understand the motion of the arrow. When it is shot up in the night sky, it initially moves upward against the force of gravity. At the top of its path, the arrow momentarily comes to rest before coming back down. During this brief moment of rest, the acceleration is zero.

To understand why this is the case, consider that acceleration is the rate of change of velocity. When the arrow is at the top of its path, its velocity is zero because it momentarily stops moving. Consequently, there is no change in velocity, and therefore, the acceleration at the top of its path is zero.

2.) To determine whether Juan's car is slowing down or speeding up, we need to consider the sign of the acceleration. In this case, since the acceleration is given as -2.76 m/s^2, the negative sign indicates that the acceleration is directed opposite to the positive direction of motion (in this case, negative velocity means moving in the opposite direction to the positive direction represented by 43 m/s).

Because the acceleration is negative (-2.76 m/s^2), it means that Juan's car is slowing down. The negative acceleration implies a decrease in velocity, indicating a deceleration or slowdown.