Estimate the amount of 1.0m NaOH in ml required to neutralize 5.0g of KHP

I'm assuming you meant 1.0 M and not 1.0m. You need to learn the difference.

mols KHP = mass/molar mass = 5/204 = about 0.025
mols NaOH needed = 0.025
M NaOH = mols NaOH/L NaOH
M = 1.0; mols = 0.025 and L = mols/M = 0.025/1 = about 0.025 L or about 25 mL.

What mass of Potassium Hydrogen Phthalate (KHP) will just neutralize 18 mL of 0.20 M NaOH?

To estimate the amount of 1.0M NaOH required to neutralize 5.0g of KHP (Potassium Hydrogen Phthalate), we need to use the balanced chemical equation and stoichiometry.

The balanced chemical equation for the neutralization reaction between NaOH and KHP is:

NaOH + KHP → NaKP + H2O

From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of KHP. The molar mass of KHP is approximately 204.23 g/mol.

First, we need to calculate the number of moles of KHP in 5.0g. We can use the formula:

moles = mass / molar mass

moles of KHP = 5.0g / 204.23 g/mol

Next, since the reaction is 1:1 in terms of moles of NaOH to moles of KHP, the number of moles of NaOH required will be the same as the moles of KHP.

Now, we can use the molarity (M) of NaOH and the number of moles of NaOH to calculate the volume (in mL) of NaOH solution required.

Molarity = moles / volume (in L)

1.0M = moles / volume (in L)

volume (in L) = moles / Molarity

volume (in mL) = volume (in L) * 1000

So, to calculate the volume of 1.0M NaOH required, we substitute the values:

volume of NaOH (in mL) = (moles of NaOH / Molarity) * 1000

volume of NaOH (in mL) = (moles of KHP / 1.0) * 1000

Now, let's substitute the calculated values into the equation:

volume of NaOH (in mL) = (5.0g / 204.23 g/mol) * 1000

After performing the calculations, we get:

volume of NaOH (in mL) ≈ 24.5 mL

Therefore, approximately 24.5 mL of 1.0M NaOH is estimated to be required to neutralize 5.0g of KHP.

To estimate the amount of 1.0M NaOH required to neutralize 5.0g of KHP, you'll need to use a balanced chemical equation and the concept of stoichiometry.

1. Start by writing the balanced chemical equation for the reaction between NaOH and KHP (potassium hydrogen phthalate):
KHP + NaOH → NaKP + H2O

2. From the equation, you can see that the molar ratio between KHP and NaOH is 1:1. This means that one mole of KHP reacts with one mole of NaOH.

3. Determine the molar mass of KHP:
The molar mass of KHP can be calculated by adding up the atomic masses of its constituent elements. The molecular formula of KHP is C8H5KO4, so you'll need to find the atomic masses of carbon (C), hydrogen (H), potassium (K), and oxygen (O) and calculate the molar mass.

4. Convert the mass of KHP (given as 5.0g) to moles:
Divide the mass of KHP by its molar mass to get the number of moles.

5. Since the reaction between KHP and NaOH has a 1:1 molar ratio, the number of moles of KHP is also the number of moles of NaOH required.

6. Finally, convert the moles of NaOH to milliliters (ml):
Since the concentration of NaOH is given as 1.0 M (moles per liter), you'll need to calculate the volume of NaOH in liters first and then convert it to milliliters. Use the formula V = (n / C), where V is the volume in liters, n is the number of moles of NaOH, and C is the concentration of NaOH.

By following these steps, you can estimate the amount of 1.0 M NaOH in ml required to neutralize 5.0g of KHP.