A golf ball strikes a hard, smooth floor at an angle of 33.1 ° and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0172 kg, and its speed is 59.2 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)

Question

A golf ball strikes a hard, smooth floor at an angle of 33.1 ° and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0172 kg, and its speed is 59.2 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)

Answer 1

find the vertical component of momentum of the ball, double it...think out why..

Answer 2

I did 59.2 sin (33.1) for a new velocity. Then multiplied by my mass for the change in momentum (impulse). I don't think that's correct.

Answer 3

I get why it's twice. There's a rebound. But I don't understand how to do the vertical component. Is that correct how i showed above? but multiplied by 2?

Answer 4

To find the magnitude of the impulse applied to the golf ball by the floor, we can follow these steps:

Step 1: Determine the initial and final vertical velocities of the ball.
Given that the angle of incidence (angle of striking the floor) is equal to the angle of reflection (rebounding), the vertical component of the ball's velocity does not change. Therefore, the initial and final vertical velocities remain the same as 59.2 m/s.

Step 2: Calculate the change in vertical momentum.
The change in momentum is given by the equation:
Δp = m * Δv
where Δp is the change in momentum, m is the mass of the ball, and Δv is the change in velocity.

Since the vertical component of the ball's momentum changed during impact, we only need to consider the vertical change in momentum. The mass of the ball is given as 0.0172 kg, and the change in velocity is the difference between the initial and final vertical velocities, which is 0 m/s since the vertical velocities remain the same.

Therefore, the change in vertical momentum is:
Δp = 0.0172 kg * (0 m/s - 0 m/s) = 0 kg*m/s

Step 3: Calculate the magnitude of the impulse.
The magnitude of the impulse is equal to the magnitude of the change in momentum. In this case, since the change in vertical momentum is equal to zero, the magnitude of the impulse is also zero.

Therefore, the magnitude of the impulse applied to the golf ball by the floor is 0 kg*m/s.