If 4.7M SrLi2 solution is diluted to 45L, what is the molarity of the diluted solution?
Sr WHAT?
How much of that Sr whatever was used.
mL1 x M1 = mL2 x M2
It is SrCl2 not SrLi2
That equation will tell you how to dilute it. But you still must have the amount of the SrCl2 used. Let's say you used 100 mL, then
100mL x 4.7M = 45000 mL x M
Solve for M of the 45 L material.
To find the molarity of the diluted solution, we need to use the formula:
M1V1 = M2V2
where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution
From the given information, we can identify the values as follows:
M1 = 4.7 M (initial molarity of the solution)
V1 = unknown
M2 = unknown (final molarity of the solution)
V2 = 45 L (final volume of the solution)
Now, we can rearrange the formula to solve for M2:
M2 = (M1V1) / V2
To find the final molarity, we need to rearrange the formula and substitute the given values:
M2 = (4.7 M * V1) / 45 L
Since we don't have the initial volume (V1), we cannot directly calculate the final molarity using the given information. You would need to provide the initial volume in order to solve for M2.