A 63.8 kg woman lifts herself 36.6 cm each time she does a chin-up. What force does she exert in lifting herself to the chin position?
And, how much positive work does she do in pulling herself up once?
Well, if the woman is lifting herself during a chin-up, we can say she's taking some "selfie" to a whole new level! Now, let's get down to business.
To determine the force she exerts in lifting herself to the chin position, we need to consider the gravitational force acting on her. The force she exerts is equal to her weight (mg), where m is her mass and g is the acceleration due to gravity.
So, the force she exerts can be calculated as (63.8 kg) x (9.8 m/s^2) = 626.44 N.
Now, let's talk about the positive work she does in pulling herself up once. Work is defined as the force exerted on an object multiplied by the distance over which the force is applied.
Since she lifts herself a distance of 36.6 cm, we need to convert it to meters by dividing it by 100. So, 36.6 cm = 0.366 m.
The positive work she does can be calculated as the force exerted (626.44 N) multiplied by the distance (0.366 m), which results in approximately 228.77 Joules.
So, next time you see someone doing a chin-up, remember the tremendous force and work they put into it!
To calculate the force exerted by the woman in lifting herself to the chin position, you can use the equation:
Force = Mass x Acceleration
In this case, the force refers to the force exerted by the woman, the mass is her weight, and the acceleration is the acceleration due to gravity.
1. Calculate the force:
To find the woman's weight, multiply her mass by the acceleration due to gravity, which is approximately 9.8 m/s^2.
Weight = Mass x Acceleration due to gravity
Weight = 63.8 kg x 9.8 m/s^2 = 625.24 N
So, the woman exerts a force of 625.24 Newtons in lifting herself to the chin position.
To calculate the positive work done in pulling herself up once, you use the equation:
Work = Force x Distance
1. Convert the distance from centimeters to meters:
Distance = 36.6 cm / 100 = 0.366 meters
2. Calculate the work:
Work = Force x Distance
Work = 625.24 N x 0.366 m = 228.16 Joules
Therefore, the woman does 228.16 Joules of positive work in pulling herself up once.
a. F = m*g = 63.8 * 9.8 = 625.2 N.
b. Work = F*d = 625.2 * 0.366 = 228.8 J.