Belle is swimming in the lake and is 230 feet from shore. She starts to head back to shore at arate of 2ft/s. Ten seconds later, Max hops in a row boat and rows towards Belle at a rate of 5 ft/s. How many seconds will Bell have been swimming when Max reaches her?
between the two, they cover the 230 ft. So, after Belle has been swimming x seconds,
2x + 5(x-10) = 230
2x + 5x - 50 = 230
7x = 280
x = 40
To find the number of seconds Belle has been swimming when Max reaches her, we first need to determine the time it takes for Max to reach Belle.
Let's calculate the time it takes for Max to reach Belle:
Since Belle is initially 230 feet from the shore and starts heading back at a rate of 2 ft/s, we can use the formula: distance / rate = time.
The distance Max needs to cover to reach Belle is 230 feet, and Max's rowing speed is 5 ft/s.
So, the time it takes for Max to reach Belle is: 230 feet / 5 ft/s = 46 seconds.
Now we need to determine how many seconds Belle has been swimming when Max reaches her. We know that Max starts rowing 10 seconds after Belle starts swimming.
Since the time it takes for Max to reach Belle is 46 seconds, and Max starts 10 seconds after Belle starts swimming, we add those two times together:
Time Belle has been swimming = 46 seconds + 10 seconds = 56 seconds.
Therefore, Belle will have been swimming for 56 seconds when Max reaches her.