If it takes 6 men 4h to dig a hole 6m deep,how long will it take 10 men to dig a hole 5m deep?

6 men --- 4 hrs --- 6m deep

1 man ---24 hrs --- 6m deep
10 men 24/10 hrs -- 6 m deep
10 men 2.4 hrs --- 6 m deep
10 men 2.4/6 hrs --1 m deep
10 men .4 hrs ===1 m deep
10 men .4(5) hrs --- 5 m deep

10 men 2 hrs ---- 5 m deep

OR

it takes 24 manhrs to dig a 6 m deep hole
it takes 4 manhrs to dig a 1 m deep hole
it takes 20 manhrs to dig a 5 m deep hole
so it takes 10 men 2 hrs to dig a 5 m deep hole

Thank you very much!!!


then how to do this qn?

y is directly proportional to the square root of x.If y is quadrupled,find the percentage change in x.

y1/y2 = √x1/√x2

1/4 = √x1/√x2
√x2 = 4√x1
square both sides
x2 = 16x1
x2/x1 = 16/1 or 1600 %

e.g. suppose x = 36
then y = 6
now we want y to be quadrupled, so y = 24
and x would be such that
√x = 24 , so x = 576
percentage increase in x = 576/36 = 16
so 16 fold increase is 1600%

To find out how long it will take 10 men to dig a hole 5m deep, we can use the concept of man-hours.

First, we know that it takes 6 men 4 hours to dig a hole 6m deep. This means that they work together to complete a total of 6 x 4 = 24 man-hours of work.

Next, we need to calculate the number of man-hours required to dig a hole 5m deep. Since the depth of the hole is decreasing, we can assume that digging the hole will be roughly proportional to the depth. So, we can set up a proportion:

6m depth / 24 man-hours = 5m depth / x man-hours

Cross-multiplying, we get:

6m depth * x man-hours = 5m depth * 24 man-hours

Simplifying:

6x = 120

Now, dividing both sides by 6:

x = 20

Therefore, it will take 10 men a total of 20 man-hours to dig a hole 5m deep.