Calculate the mass of water having the same number of hydrogen atoms as are present in 32 gm of methane.
1 mol CH4 has 6.02E23 molecules
1 mol H2O has 6.02E23 molecules
so 1 mol CH4 has same number molecules as 1 mol H2O.
mols methane = g/molar mass = 32/16 = 2 mol CH4. That has 2*4 = 8 mols H atoms.
mols H2O vs CH4; You must multiply mols H in H2O by 2 to get mols H in CH4. So 2 mol H2O x 2 = 4 mols H2O and 4*18 = 72 g H2O. Chech that.
32g CH4 is 32/16 = 2 mols CH4 which is 2*4 = 8 mols H atoms.
72g H2O is 72/18 = 4 mols H2O which is 4*2 = 8 mols H atoms.
Bingo!
Ans:- 72 gram
Solution:-
here,
At first for methane(CH4):
N.O of mole = given mass(32)/molar mass(16) [molar mass = (12+4), given
mass= 32]
n.o of moles = 2 moles
we know that,
If 1 mole of CH4molecule = 4 moles of H atom. then,
2 moles of CH4 molecules = 8 moles of H atom
Again,
1 mole of H ====> 6.022*10^23 atoms of H. Then,
8 mole of H ====> 6.022*10^23 * 8====>4.8176*10^24 atoms of H.
for mass for H:-
6.022*10^23 atoms of H ====>1 gm of H then
4.8176*10^24 atoms of H====> 8 gm of H.
For mass of O:-
Here to get the number of oxygen(O2) in water(H2O), we have to half the number of atom of the atoms that we get from the H. It is because, look in the molecular formula of H2O there are 2 atoms of hydrogen(H) and one atom of oxygen(O). so, me must understand that the one atom of oxygen uses two atom of hydrogen(H).
therefore,
no of oxygen atom= (4.8176*10^24/ 2)= 2.4088*10^24 atoms
finally, For oxygen(O):-
if 6.022*10^23 atoms ====> 16 gram of O then
2.4088*10^24 atoms =====> (16/6.022*10^23)*2.4088*10^24====>64- gram
hence, the total mass or weight of water = 64+ 8 = 72 gram.
I hope you have understood! Thank You!
To calculate the mass of water having the same number of hydrogen atoms as are present in 32 g of methane, you need to determine the number of hydrogen atoms in 32 g of methane and then convert that to the mass of water.
Let's start by calculating the number of hydrogen atoms in 32 g of methane (CH4).
1 molecule of methane (CH4) contains 4 hydrogen atoms.
The molecular weight of methane (CH4) is:
C = 12.01 g/mol
H = 1.008 g/mol
Calculating the molecular weight of methane:
1 × C = 1 × 12.01 = 12.01 g/mol
4 × H = 4 × 1.008 = 4.032 g/mol
Total molecular weight of methane (CH4) = 12.01 + 4.032 = 16.042 g/mol
Now, to calculate the number of moles of methane in 32 g:
Number of moles = given mass / molecular weight
Number of moles = 32 g / 16.042 g/mol ≈ 1.994 mol
Since 1 mole of methane contains 4 moles of hydrogen atoms, the number of hydrogen atoms in 1.994 mol of methane is:
Number of hydrogen atoms = 1.994 mol × 4 = 7.976 mol
Now, to calculate the mass of water having the same number of hydrogen atoms (7.976 mol):
1 molecule of water (H2O) contains 2 hydrogen atoms.
The molecular weight of water (H2O) is:
H = 1.008 g/mol
O = 16.00 g/mol
Calculating the molecular weight of water:
2 × H = 2 × 1.008 = 2.016 g/mol
1 × O = 1 × 16.00 = 16.00 g/mol
Total molecular weight of water (H2O) = 2.016 + 16.00 = 18.02 g/mol
Now, to calculate the mass of water:
Mass of water = number of moles × molecular weight
Mass of water = 7.976 mol × 18.02 g/mol ≈ 143.88 g
Therefore, the mass of water having the same number of hydrogen atoms as are present in 32 g of methane is approximately 143.88 grams.
To calculate the mass of water having the same number of hydrogen atoms as are present in 32 gm of methane, you need to consider the molecular formula of each compound and compare the number of hydrogen atoms.
Let's start with the molecular formula of methane (CH4). In methane, there is one carbon atom (C) and four hydrogen atoms (H).
Next, we need to find the molar mass of methane. The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of hydrogen (H) is approximately 1.01 g/mol. Adding these values together, we get:
(1 × 12.01 g/mol) + (4 × 1.01 g/mol) = 16.05 g/mol
So, 1 mole of methane weighs approximately 16.05 grams.
Now, let's consider water (H2O). In water, there are two hydrogen atoms (H) and one oxygen atom (O).
To find the mass of water containing the same number of hydrogen atoms as in 32 grams of methane, we need to find out how many moles of methane are present in 32 grams. We can calculate this using the molar mass of methane:
32 g ÷ 16.05 g/mol = 1.99 moles of methane
Since one mole of methane contains four moles of hydrogen atoms, we can calculate the number of moles of hydrogen atoms:
1.99 moles of methane × 4 moles of H = 7.96 moles of H
Now, we can calculate the mass of water containing the same number of hydrogen atoms. Since water has two hydrogens per molecule, we divide the number of moles of hydrogen atoms by 2:
7.96 moles of H ÷ 2 = 3.98 moles of water
Finally, we calculate the mass of water by multiplying the number of moles by the molar mass of water, which is approximately 18.02 g/mol:
3.98 moles of water × 18.02 g/mol = 71.72 grams of water
Therefore, the mass of water containing the same number of hydrogen atoms as in 32 grams of methane is approximately 71.72 grams.