In some solid calcium carbonate samples, calcium bicarbonate Ca(HCO3)2. Write a balanced equation for its reaction with hydrochloric acid.
CaCO3 + HCL= Ca^2+ (aq) + HCL + Ca(HCO3)2
I don't know if I have written the reactions and products correctly?
I'm not sure I understand the question. Is that a mixture of CaCO3 and Ca(HCO3)2. Or are you asking for the rxn you wrote?
The rxn you wrote can be corrected as follows:
2CaCO3 + 2HCl ==> Ca(HCO3)2 + CaCl2
or if you decomose the CO3^2- all way it will be
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2
The balanced equation for the reaction between calcium bicarbonate (Ca(HCO3)2) and hydrochloric acid (HCl) is:
Ca(HCO3)2 + 2HCl -> CaCl2 + 2H2O + 2CO2
To determine whether you have written the reactions and products correctly, we can go through the balancing process.
1. Start by balancing the calcium (Ca) atoms. There is one Ca atom on the left side, so we need one CaCl2 on the right side.
Ca(HCO3)2 + 2HCl -> CaCl2 + ...
2. Next, balance the chloride (Cl) atoms. There are two Cl atoms on the right side, so we need two HCl on the left side.
Ca(HCO3)2 + 2HCl -> CaCl2 + H2O + ...
3. Next, balance the hydrogen (H) atoms. There are four H atoms on the left side (2 from Ca(HCO3)2 and 2 from 2HCl), so we need two H2O on the right side.
Ca(HCO3)2 + 2HCl -> CaCl2 + 2H2O + ...
4. Finally, balance the carbon (C) and oxygen (O) atoms. There are two C atoms and six O atoms on the left side (2 from Ca(HCO3)2), so we need two CO2 on the right side.
Ca(HCO3)2 + 2HCl -> CaCl2 + 2H2O + 2CO2
Therefore, the balanced equation is:
Ca(HCO3)2 + 2HCl -> CaCl2 + 2H2O + 2CO2