A truck with mass 2000 kg tows a boat and trailer of total mass 500 kg. The rolling coefficient of friction for the truck is 0.080 and for the trailer is 0.050. The force of the truck’s drive wheels pushing backward on the pavement is 3.0 kN. (a) Determine the acceleration rate of the truck and trailer moving forward together. (b) Determine the amount of force the truck’s hitch exerts forward on the trailer.
I really don't know how to explain it, so here is just the answers.
"a. 0.47 m/s2
b. 480 N"
I hope this helps! :)
Oops, I am Anonymous. Anyways, here's everything again:
"I really don't know how to explain it, so here is just the answers.
"a. 0.47 m/s2
b. 480 N"
I hope this helps! :)"
A person rows a boat at a speed of 5.0km/hr in still water. The person heads directly across a river that flows at a speed of 5.0km/hr. Determine the magnitude and direction of the boat resultant velocity
To determine the acceleration rate of the truck and trailer moving forward together, we'll use Newton's second law of motion, which states that the net force on an object is equal to its mass multiplied by its acceleration (F = ma).
(a) First, let's calculate the total mass of the truck and trailer. The mass of the truck is given as 2000 kg, and the mass of the boat and trailer is given as 500 kg. So, the total mass (m_total) is 2000 kg + 500 kg = 2500 kg.
Next, let's calculate the net force acting on the truck and trailer system. The force of the truck's drive wheels pushing backward on the pavement is given as 3.0 kN. We can convert this to Newtons by multiplying by 1000. So, the net force (F_net) is 3.0 kN × 1000 N/kN = 3000 N.
Now, we can substitute these values into Newton's second law of motion to find the acceleration (a). Rearranging the equation, we have a = F_net / m_total:
a = 3000 N / 2500 kg
Calculating the value, we find:
a ≈ 1.2 m/s^2
Therefore, the acceleration rate of the truck and trailer moving forward together is approximately 1.2 m/s^2.
(b) To determine the amount of force the truck's hitch exerts forward on the trailer, we need to consider the forces acting on the truck and trailer system. The force exerted by the truck's hitch (F_hitch) is equal in magnitude but opposite in direction to the net force (F_net), as it should cancel out the net force to maintain equilibrium.
So, the force exerted by the truck's hitch on the trailer is also 3000 N in the forward direction.