On June 9, 1988, Sergei Bubka broke the world pole-vaulting record for the 8th time in four years by attaining a height of 6.14 m. How long did it take Bubka to return to the ground from the highest part of his vault?
Well, let me calculate that for you.
Considering the laws of physics, gravity, and some extremely approximate estimations, it would take Sergei Bubka approximately 1.2 seconds to return to the ground from the highest part of his vault. Of course, this estimation disregards any wind resistance, the potential presence of anti-gravity clowns, or any other unpredictable factors. So, take it with a grain of circus salt! š¤”
To calculate the time it took for Sergei Bubka to return to the ground from the highest part of his vault, we need to consider the laws of physics and assume ideal conditions.
1. First, we need to determine the time it took for Bubka to reach the highest point of his vault. Considering that the pole-vaulting is a projectile motion, the time to reach the highest point is equal to the time it takes to clear the height of 6.14 m.
2. The formula to calculate the time taken to reach the highest point is: t = ā(2h/g), where h is the height and g is the acceleration due to gravity (approximately 9.8 m/sĀ²).
3. Plugging in the values, we have: t = ā(2 * 6.14 / 9.8) ā ā1.255 ā 1.12 seconds (rounded to two decimal places).
4. Since the time to reach the highest point represents the ascent phase of the vault, we need to double this time to account for the descent phase as well.
5. Thus, the total time it took Sergei Bubka to return to the ground from the highest part of his vault is approximately 1.12 seconds * 2 = 2.24 seconds.
Therefore, it took Bubka approximately 2.24 seconds to return to the ground from the highest part of his vault.
To determine how long it took Sergei Bubka to return to the ground from the highest part of his vault, we need to consider the physics of the situation.
When an object is in free fall, as Bubka would be when he reaches the peak of his vault, we can use the equation for free-fall motion to calculate the time it takes to return to the ground. The equation is:
y = (1/2) * g * t^2
Where:
y = displacement (in this case, the height of the vault)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
In this case, the displacement is given as 6.14 m.
Rearranging the equation, we have:
t^2 = (2 * y) / g
t = sqrt((2 * y) / g)
Plugging in the values, we get:
t = sqrt((2 * 6.14) / 9.8)
t ā sqrt(1.25)
t ā 1.12 seconds
Therefore, it took approximately 1.12 seconds for Sergei Bubka to return to the ground from the highest part of his vault.
h = 0.5g*t^2 = 6.14 m.
4.9t^2 = 6.14
t^2 = 1.253
Tf = 1.12 s. = Fall time.