Jordan throws a golfball straight up from the top of a building 50 meters high. The initial speed of the golfball is 20 m/s and it just misses the edge of the roof when it eventually falls. Neglecting air resistance, find the velocity of the golfball just at the instant it hits the ground.
h = ho + (V^2-(Vo^2))/2g
h = 50 + (0-(20^2))/-19.6 = 70.4 m. Above gnd.
V^2 = Vo^2 + 2g*h = 0 + 19.6*70.4 = 1380
V = 37.1 m/s.