An apple falls from a tree and hits the ground 8.83 m below. With what speed will it hit the ground? The acceleration of gravity is 9.8 m/s2 .

Answer in units of m/s

87.89 9788

To find the speed at which the apple hits the ground, we can use the equation of motion for an object falling freely under the influence of gravity:

v^2 = u^2 + 2as

where:
v = final velocity (speed at which the apple hits the ground)
u = initial velocity (which is 0 because the apple starts from rest when it falls)
a = acceleration due to gravity (9.8 m/s^2)
s = displacement (the distance the apple falls, which is 8.83 m)

Plugging in the values into the equation:

v^2 = 0^2 + 2 * 9.8 * 8.83

v^2 = 0 + 172.2468

v ≈ √172.2468

v ≈ 13.130 m/s

So, the speed at which the apple hits the ground is approximately 13.130 m/s.