A car drives at 15 m/s and has an air resistance force of 244 N. What is the air resistance force at 30 m/s?
given laminar flow, the drag force is proportional to the radius of the sphere and to its velocity. Double the radius, double the drag force. Double the velocity, double the drag force. This is known as Stokes Drag
If you don't have laminar flow, then you need to figure Quadratic Drag, drag force is proportional to the square of velocity and to the cross-sectional area of the object. For which you'll need to id the correct Reynolds Number
To find the air resistance force at 30 m/s, we need to understand how air resistance is related to velocity.
Air resistance is generally proportional to the square of the velocity. This means that as the velocity of the car doubles, the air resistance force will quadruple. Conversely, if the velocity is halved, the air resistance force will be reduced to one-fourth.
In this case, the car is moving at 15 m/s, and the air resistance force is 244 N. We can use this information to calculate the air resistance force at 30 m/s.
First, we need to determine the ratio between the velocities. We can do this by dividing the desired velocity (30 m/s) by the initial velocity (15 m/s):
Ratio = 30 m/s / 15 m/s = 2
Next, we square the ratio to determine how the air resistance force changes:
Ratio squared = 2^2 = 4
Since the air resistance force is proportional to the square of the velocity, we can multiply the initial air resistance force (244 N) by the ratio squared to obtain the air resistance force at 30 m/s:
Air resistance force at 30 m/s = 244 N * 4 = 976 N
Therefore, the air resistance force at 30 m/s is 976 N.