If your carboxylic acid is benzoic acid, how many moles of benzoic acid are present in your sample (0.30g, and it is a mixture of three components of equal mass)?
You've said it funny. Do you mean it is 0.1g benzoic acid + 0.1 of X and 0.1 g of Y? If so then
mols = g/molar mass = 0.1g/molar mass benzoic acid which is about 122.
If that isn't what you meant and the mass benzoic acid is 0.3 g, then 0.3/122 = mols benzoic acid.
To determine the number of moles of benzoic acid present in the sample, you need to use the molar mass of benzoic acid.
Benzoic acid has a molar mass of 122.12 g/mol.
First, calculate the number of moles in 0.30 g of benzoic acid:
moles = mass / molar mass
moles = 0.30 g / 122.12 g/mol
moles ≈ 0.0025 mol
Since the sample is a mixture of three components of equal mass, each component's mass is one-third of the total mass.
Therefore, the number of moles of benzoic acid present in the sample is:
moles of benzoic acid = moles × fraction of benzoic acid
moles of benzoic acid = 0.0025 mol × 1/3
moles of benzoic acid ≈ 0.00083 mol
So, approximately 0.00083 moles of benzoic acid are present in your sample.